JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A block of \(\sqrt{3}\,kg\) is attached to a string whose other end is attached to the wall. An unknown force \(F\) is applied so that the string makes an angle of \(30^{\circ}\) with the wall. The tension \(T\) is \(...........\,N\) :(Given \(g =10\,ms ^{-2}\) )

- A \(20\)
- B \(25\)
- C \(10\)
- D \(15\)
Answer & Solution
Correct Answer
(A) \(20\)
Step-by-step Solution
Detailed explanation
\(\theta=30^{\circ}\) \(\cos \theta=\frac{\sqrt{3} g }{ T }\) \(\Rightarrow \frac{\sqrt{3}}{2}=\frac{\sqrt{3} g }{ T }\) \(\Rightarrow T =20\,N\)
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