JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
An object \(AB\) is placed \(15\text{ cm}\) on the left of a convex lens \(P\) of focal length \(10\text{ cm}\). Another convex lens \(Q\) is now placed \(15\text{ cm}\) right of lens \(P\). If the focal length of lens \(Q\) is \(15\text{ cm}\), the final image is _______.
- A virtual, formed at \(7.5\text{ cm}\) right of lens \(Q\), with a size bigger than that of \(AB\)
- B real, formed at \(7.5\text{ cm}\) right of lens \(Q\), with a size same as that of \(AB\)
- C formed at infinity.
- D real, formed at \(7\text{ cm}\) right of lens \(Q\), with a size smaller than that of \(AB\)
Answer & Solution
Correct Answer
(B) real, formed at \(7.5\text{ cm}\) right of lens \(Q\), with a size same as that of \(AB\)
Step-by-step Solution
Detailed explanation
For lens \(P\): \(\dfrac{1}{v_1} - \dfrac{1}{u_1} = \dfrac{1}{f_1}\) \(\dfrac{1}{v_1} - \dfrac{1}{-15} = \dfrac{1}{10}\) \(\dfrac{1}{v_1} = \dfrac{1}{10} - \dfrac{1}{15} = \dfrac{1}{30} \Rightarrow v_1 = 30\text{ cm}\) Magnification…
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