JEE Mains · Physics · STD 12 - 12. atoms
Angular momentum of an electron in a hydrogen atom is \(\dfrac{3h}{\pi}\), then the energy of the electron is _______ eV.
- A \(-1.51\)
- B \(-0.85\)
- C \(-0.38\)
- D \(-0.28\)
Answer & Solution
Correct Answer
(C) \(-0.38\)
Step-by-step Solution
Detailed explanation
The angular momentum of an electron in the \(n\)-th orbit of a hydrogen atom is given by Bohr's quantization rule: \(L = \dfrac{nh}{2\pi}\) Given that the angular momentum is \(\dfrac{3h}{\pi}\), we can equate the two expressions: \(\dfrac{nh}{2\pi} = \dfrac{3h}{\pi}\) Solving…
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