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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases

An ideal gas is enclosed in a cylinder at pressure of \(2\,atm\) and temperature, \(300\,K.\) The mean time between two successive collisions is \(6 \times 10^{-8}\, s.\) If the pressure is doubled and temperature is increased to \(500\,K,\) the mean time between two successive collisions will be close to

  1. A \(2\times 10^{-7}\,s\)
  2. B \(4\times 10^{-8}\,s\)
  3. C \(0.5\times 10^{-8}\,s\)
  4. D \(3\times 10^{-6}\,s\)
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Answer & Solution

Correct Answer

(B) \(4\times 10^{-8}\,s\)

Step-by-step Solution

Detailed explanation

\({\text { The mean time between two collision } \propto \frac{P}{\sqrt{T}}} \) \({\qquad \frac{\Delta t_{1}}{\Delta t_{2}}=\frac{P_{1}}{P_{2}} \times \frac{\sqrt{T_{2}}}{\sqrt{T_{1}}}} \)…
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