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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2019
  • Hard
  • MCQ

An ideal gas is enclosed in a cylinder at pressure of \(2\,atm\) and temperature, \(300\,K.\) The mean time between two successive collisions is \(6 \times 10^{-8}\, s.\) If the pressure is doubled and temperature is increased to \(500\,K,\) the mean time between two successive collisions will be close to

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Correct Answer

(B) \(4\times 10^{-8}\,s\)

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Detailed explanation

\({\text { The mean time between two collision } \propto \frac{P}{\sqrt{T}}} \)

\({\qquad \frac{\Delta t_{1}}{\Delta t_{2}}=\frac{P_{1}}{P_{2}} \times \frac{\sqrt{T_{2}}}{\sqrt{T_{1}}}} \)

\({\Rightarrow \quad \frac{6 \times 10^{-8}}{\Delta t_{2}}=(\sqrt{\frac{3}{5}}) \times 2} \)

\({\Rightarrow \quad \Delta t_{2}=6 \times 10^{-8} \times \frac{1}{2} \sqrt{\frac{5}{3}} \approx 4 \times 10^{-8} \text { sec }}\)

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