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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2023
  • Medium
  • Numerical

The velocity of a particle executing SHM varies with displacement \(( x )\) as \(4 v ^2=50- x ^2\). The time period of oscillations is \(\frac{x}{7} s\). The value of \(x\) is \(............\) \(\left(\right.\) Take \(\left.\pi=\frac{22}{7}\right)\)

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Answer & Solution

Correct Answer

(C) \(88\)

Step-by-step Solution

Detailed explanation

\(4 v ^2=50- x ^2\)

\(\Rightarrow \quad v =\frac{1}{2} \sqrt{50- x ^2}\)

\(\omega=\frac{1}{2}\)

\(T =\frac{2 \pi}{\omega}=4 \pi=\frac{88}{7}\)

\(x =88\)

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