JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2023
- Medium
- Numerical
The velocity of a particle executing SHM varies with displacement \(( x )\) as \(4 v ^2=50- x ^2\). The time period of oscillations is \(\frac{x}{7} s\). The value of \(x\) is \(............\) \(\left(\right.\) Take \(\left.\pi=\frac{22}{7}\right)\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(88\)
Step-by-step Solution
Detailed explanation
\(4 v ^2=50- x ^2\)
\(\Rightarrow \quad v =\frac{1}{2} \sqrt{50- x ^2}\)
\(\omega=\frac{1}{2}\)
\(T =\frac{2 \pi}{\omega}=4 \pi=\frac{88}{7}\)
\(x =88\)
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