JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
If the length of the pendulum in pendulum clock increases by \(0.1\, \%\), then the error in time per day is: (in \(s\))
- A \(86.4\)
- B \(4.32\)
- C \(43.2\)
- D \(8.64\)
Answer & Solution
Correct Answer
(C) \(43.2\)
Step-by-step Solution
Detailed explanation
\({T}=2 \pi \sqrt{\frac{\ell}{g}}\) \(\frac{\Delta {T}}{{T}}=\frac{1}{2} \frac{\Delta \ell}{\ell}\) \(\Delta {T}=\frac{1}{2} \times \frac{0.1}{100} \times 24 \times 3600\) \(\Delta {T}=43.2\)
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