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JEE Mains · Maths · STD 12 - 6. Application of derivatives

Let \(\mathrm{P}(\mathrm{h}, \mathrm{k})\) be a point on the curve \(\mathrm{y}=\mathrm{x}^{2}+7 \mathrm{x}+2\) nearest to the line, \(y=3 x-3 .\) Then the equation of the normal to the curve at \(\mathrm{P}\) is 

  1. A \(x+3 y-62=0\)
  2. B \(x-3 y-11=0\)
  3. C \(x-3 y+22=0\)
  4. D \(x+3 y+26=0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(x+3 y+26=0\)

Step-by-step Solution

Detailed explanation

Let \(\mathrm{L}\) be the common normal to parabola \(y=x^{2}+7 x+2\) and line \(y=3 x-3\) \(\Rightarrow\) slope of tangent of \(y=x^{2}+7 x+2\) at \(P=3\) \(\left.\Rightarrow \frac{\mathrm{d} \mathrm{y}}{\mathrm{dx}}\right]_{\mathrm{For} \mathrm{P}}=3\)…
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