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JEE Mains · Physics · STD 12 - Electromagnetic waves
  • JEE Mains 2024
  • Hard
  • MCQ

In the given electromagnetic wave \(E_y=600 \sin (\omega t-k x) \mathrm{Vm}^{-1}\), intensity of the associated light beam is what? (in \(\mathrm{W} / \mathrm{m}^2\) ); (Given \(\epsilon_0=\) \(\left.9 \times 10^{-12} \mathrm{C}^{-2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}\right)\)

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Answer & Solution

Correct Answer

(A) \(486\)

Step-by-step Solution

Detailed explanation

\(Intensity =\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2 \mathrm{c}\)

\(=\frac{1}{2} \times 9 \times 10^{-12} \times(600)^2 \times 3 \times 10^8\)

\(=\frac{9}{2} \times 36 \times 3=486 \mathrm{w} / \mathrm{m}^2\)

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