JEE Mains · Physics · STD 12 - 12. atoms
\(\sqrt{d_{1}}\) and \(\sqrt{d_{2}}\) are the impact parameters corresponding to scattering angles \(60^{\circ}\) and \(90^{\circ}\) respectively, when an \(\alpha\) particle is approaching a gold nucleus. For \(d_{1}=x d_{2}\), the value of \(x\) will be ________
- A \(3\)
- B \(4\)
- C \(5\)
- D \(7\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
\(\sqrt{d} \propto \cot \frac{\theta}{2}\) \(\cot ^{2} 30^{\circ}=x \cot ^{2} 45^{\circ}\) \(3=x\)
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