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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

An engine is attached to a wagon through a shock absorber of length \(1.5\, {m}\). The system with a total mass of \(40,000\, {kg}\) is moving with a speed of \(72\, {kmh}^{-1}\) when the brakes are applied to bring it to rest. In the process of the system being brought to rest, the spring of the shock absorber gets compressed by \(1.0\, {m}\). If \(90\, \%\) of energy of the wagon is lost due to friction, the spring constant is \(....\, \times 10^{5}\, {N} / {m}\)

  1. A \(16\)
  2. B \(400\)
  3. C \(1.6\)
  4. D \(160\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(16\)

Step-by-step Solution

Detailed explanation

\(\text { Work }=\Delta K . E\) \(W_{\text {friction }}+W_{\text {spring }}=0-\frac{1}{2} m v^{2}\) \(-\frac{90}{100}\left(\frac{1}{2} m v^{2}\right)+W_{\text {Spring }}=-\frac{1}{2} m v^{2}\) \({W}_{\text {spring }}=-\frac{10}{100} \times \frac{1}{2} {mv}^{2}\)…
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