JEE Mains · Physics · STD 11 - 3.2 motion in plane
A particle is moving in a circle of radius \(50 \mathrm{~cm}\) in such a way that at any instant the normal and tangential components of its acceleration are equal. If its speed at \(t=0\) is \(4 \mathrm{~m} / \mathrm{s}\), the time taken to complete the first revolution will be \(\frac{1}{\alpha}\left[1-\mathrm{e}^{-2 \pi}\right] \mathrm{s}\), where \(\alpha=\) _______.
- A \(8\)
- B \(5\)
- C \(98\)
- D \(45\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
\( \left|\overrightarrow{\mathrm{a}}_{\mathrm{c}}\right|=\left|\overrightarrow{\mathrm{a}}_{\mathrm{t}}\right| \) \( \frac{\mathrm{v}^2}{\mathrm{r}}=\frac{\mathrm{dv}}{\mathrm{dt}} \)…
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