JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Two iron solid discs of negligible thickness have radius \(R_1\) and \(R_2\) and moment of intertia \(I_1\) and \(I_2\), respectively. For \(R_2=2 R_1\), the ratio of \(I_1\) and \(I_2\) would be \(1 / x\), where \(\mathrm{x}=\) ________ -
- A 14
- B 16
- C 12
- D 10
Answer & Solution
Correct Answer
(B) 16
Step-by-step Solution
Detailed explanation
Given \(R_2=2 R_1\) \(\begin{aligned} & M_1=\sigma \times \pi R_1^2=M_o \\ & M_2=\sigma \times \pi R_2^2=M_o \\ & M_2=\sigma \times \pi R_2^2=\sigma \times \pi\left[2 R_1\right]^2=\sigma \times 4 \pi R_1^2=4 M_o \end{aligned}\)…
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