JEE Mains · Physics · STD 12 -7. Alternating current
When the \(rms\) voltages \(V_L, V_C\) and \(V_R\) are measured respectively across the inductor \(L\), the capacitor \(C\) and the resistor \(R\) in a series \(LCR\) circuit connected to an \(AC\) source, it is found that the ratio \(V_L : V_C : V_R = 1 : 2 : 3\). If the \(rms\) voltage of the \(AC\) sources is \(100\, V\), the \(V_R\) is close to........\(V\)
- A \(50\)
- B \(70\)
- C \(90\)
- D \(100\)
Answer & Solution
Correct Answer
(C) \(90\)
Step-by-step Solution
Detailed explanation
Given, \(V_{L}: V_{C}: V_{R}=1: 2: 3\) \(\mathrm{V}=100 \,\mathrm{V}\) \(\mathrm{V}_{\mathrm{R}}=?\) As we know, \(V=\sqrt{V_{R}^{2}+\left(V_{L}-V_{C}\right)^{2}}\) Solving we get, \(\mathrm{V}_{\mathrm{R}}=90\, \mathrm{V}\)
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