JEE Mains · Physics · STD 12 - Electromagnetic waves
- JEE Mains 2021
- Hard
- Numerical
An electromagnetic wave of frequency \(3\, GHz\) enters a dielectric medium of relative electric permittivity \(2.25\) from vacuum. The wavelength of this wave in that medium will be \(.......\,\times 10^{-2} \, cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(667\)
Step-by-step Solution
Detailed explanation
\(\lambda\) in vacuum \(=\frac{c}{f}=\frac{3 \times 10^{8}}{3 \times 10^{9}}=0.1\, m\)
\(\therefore \lambda\) in medium \(=\frac{0.1}{\mu}\)
Where refractive index
\(\mu=\sqrt{\mu_{z} \varepsilon_{z}}\)
Assuming non-magnetic material \(\mu_{ r }=1\)
\(\therefore \quad \mu=\sqrt{2.25}=1.5\)
\(\lambda_{ m }=\frac{0.1}{1.5}=\frac{1}{15} m =6.67 \,cm\)
\(=667 \times 10^{-2}\, cm\)
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