JEE Mains · Physics · STD 12 - 3. current electricity
A wire of uniform resistance \(\lambda \Omega / m\) is bent into a circle of radius \(r\) and another piece of wire with length 2 r is connected between points A and B \(( AOB )\) as shown in figure. The equivalent resistance between points A and B is ___________\(\Omega\).

- A \( \frac{3\pi\lambda r}{8} \)
- B \( (\pi+1)2r\lambda \)
- C \( \frac{6\pi\lambda r}{3\pi+16} \)
- D \( 2\pi\lambda r \)
Answer & Solution
Correct Answer
(C) \( \frac{6\pi\lambda r}{3\pi+16} \)
Step-by-step Solution
Detailed explanation
\( \frac{1}{R_{AB}}=\frac{2}{\lambda\pi r}+\frac{1}{\lambda.2r}+\frac{2}{\lambda.3\pi r} \) \(=\frac{1}{\lambda r}[\frac{2}{\pi}+\frac{1}{2}+\frac{2}{3\pi}] \) \( =\frac{1}{\lambda r}(\frac{12+3\pi+4}{6\pi})=\frac{1}{\lambda r}.(\frac{16+3\pi}{6\pi}) \)…
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