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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2022
  • Medium
  • Numerical

A body of mass \(M\) at rest explodes into three pieces, in the ratio of masses \(1: 1: 2\). Two smaller pieces fly off perpendicular to each other with velocities of \(30 \,ms ^{-1}\) and \(40 \,ms ^{-1}\) respectively. The velocity of the third piece will be ............... \(\,ms ^{-1}\)

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Answer & Solution

Correct Answer

(B) \(25\)

Step-by-step Solution

Detailed explanation

Mass of pieces by \(\frac{ M }{4}, \frac{ M }{4}, \frac{ M }{2}\)

conserving momentum

\(\overrightarrow{ P }_{1}+\overrightarrow{ P }_{2}+\overrightarrow{ P }_{3}=0\)

\(\overline{ P }_{3}=-\left(\overline{ P }_{1}+\overline{ P }_{2}\right)\)

As \(\overline{ P }_{1} \,and \,\overline{ P }_{2}\) are perpendicular

so \(P _{3}=\sqrt{ P _{1}^{2}+ P _{2}^{2}}\)

\(P _{3}=(50) \frac{ M }{4}\)

\( and \,P _{3}=\frac{ M }{2} v\)

so \(v =25\)