JEE Mains · Physics · STD 11 - Newtons laws of motion
- JEE Mains 2022
- Medium
- Numerical
A body of mass \(M\) at rest explodes into three pieces, in the ratio of masses \(1: 1: 2\). Two smaller pieces fly off perpendicular to each other with velocities of \(30 \,ms ^{-1}\) and \(40 \,ms ^{-1}\) respectively. The velocity of the third piece will be ............... \(\,ms ^{-1}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(25\)
Step-by-step Solution
Detailed explanation
Mass of pieces by \(\frac{ M }{4}, \frac{ M }{4}, \frac{ M }{2}\)
conserving momentum
\(\overrightarrow{ P }_{1}+\overrightarrow{ P }_{2}+\overrightarrow{ P }_{3}=0\)
\(\overline{ P }_{3}=-\left(\overline{ P }_{1}+\overline{ P }_{2}\right)\)
As \(\overline{ P }_{1} \,and \,\overline{ P }_{2}\) are perpendicular
so \(P _{3}=\sqrt{ P _{1}^{2}+ P _{2}^{2}}\)
\(P _{3}=(50) \frac{ M }{4}\)
\( and \,P _{3}=\frac{ M }{2} v\)
so \(v =25\)
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