JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
\(AC\) voltage \(V(t)=20\,sin\omega \,t\) of frequency \(50\, {Hz}\) is applied to a parallel plate capacitor. The separation between the plates is \(2\, {mm}\) and the area is \(1 \,{m}^{2}\). The amplitude of the oscillating displacement current for the applied \(AC\) voltage is ...... \(\mu {A}\). [Take \(\left.\varepsilon_{0}=8.85 \times 10^{-12} \,{F} / {m}\right]\)
- A \(21.14\)
- B \(83.57\)
- C \(55.58\)
- D \(27.79\)
Answer & Solution
Correct Answer
(D) \(27.79\)
Step-by-step Solution
Detailed explanation
From the given information, \({C}=\frac{\epsilon_{0} {A}}{{d}}={k} \frac{\epsilon_{0} \times 1}{2 \times 10^{-3}} {F}\)…
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