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JEE Mains · Physics · STD 12 - 8. Electromagnetic waves

\(AC\) voltage \(V(t)=20\,sin\omega \,t\) of frequency \(50\, {Hz}\) is applied to a parallel plate capacitor. The separation between the plates is \(2\, {mm}\) and the area is \(1 \,{m}^{2}\). The amplitude of the oscillating displacement current for the applied \(AC\) voltage is ...... \(\mu {A}\). [Take \(\left.\varepsilon_{0}=8.85 \times 10^{-12} \,{F} / {m}\right]\)

  1. A \(21.14\)
  2. B \(83.57\)
  3. C \(55.58\)
  4. D \(27.79\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(27.79\)

Step-by-step Solution

Detailed explanation

From the given information, \({C}=\frac{\epsilon_{0} {A}}{{d}}={k} \frac{\epsilon_{0} \times 1}{2 \times 10^{-3}} {F}\)…
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