JEE Mains · Physics · STD 12 -Electromagnetic induction
- JEE Mains 2021
- Medium
- Numerical
A circular conducting coil of radius \(1\, {m}\) is being heated by the change of magnetic field \(\vec {B}\) passing perpendicular to the plane in which the coil is laid. The resistance of the coil is \(2\, \mu\, \Omega\). The magnetic field is slowly switched off such that its magnitude changes in time as \(B=\frac{4}{\pi} \times 10^{-3}\, {T}\left(1-\frac{{t}}{100}\right)\) The energy dissipated by the coil before the magnetic field is switched off completely is \(E=.....\,{m} J.\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(80\)
Step-by-step Solution
Detailed explanation
\(\phi=\overrightarrow{ B } \cdot \overrightarrow{ S }\)
\(\phi=\frac{4}{\pi} \times 10^{-3}\left(1-\frac{ t }{100}\right) \cdot \pi R ^{2}\)
\(\phi=4 \times 10^{-3} \times(1)^{2}\left(1-\frac{t}{100}\right)\)
\(\varepsilon=\frac{- d \phi}{ dt }\)
\(\varepsilon=\frac{- d }{ dt }\left(4 \times 10^{-3}\left(1-\frac{ t }{100}\right)\right)\)
\(\varepsilon=4 \times 10^{-3}\left(\frac{1}{100}\right)=4 \times 10^{-5} V\)
When \(B=0\)
\(1-\frac{t}{100}=0\)
\(t=100 sec\)
\(E=\frac{\varepsilon^{2}}{R} t\)
\(E=\frac{\left(4 \times 10^{-5}\right)^{2}}{2 \times 10^{-6}} \times 100 J\)
\(E=\frac{16 \times 10^{-10} \times 100}{2 \times 10^{-6}} J\)
\(E=0.08 J\)
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