JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2025
- Medium
- Numerical
An electric dipole of dipole moment \(6 \times 10^{-6} \mathrm{Cm}\) is placed in uniform electric field of magnitude \(10^6 \mathrm{~V} / \mathrm{m}\). Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be ____ J.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) 12
Step-by-step Solution
Detailed explanation
Work done in rotating a dipole \(=\Delta U\)
\(\text { or } \begin{aligned}
W & =\left(-P E \cos \theta_f\right)-\left(-P E \cos \theta_i\right) \\
& =2 P E \quad\left(\because \theta_f=180^{\circ} \text { and } \theta_i=0^{\circ}\right) \\
& =\left(2 \times 6 \times 10^{-6} \times 10^6\right) \mathrm{J}=12 \mathrm{~J}
\end{aligned}\)
\(\text { or } \begin{aligned}
W & =\left(-P E \cos \theta_f\right)-\left(-P E \cos \theta_i\right) \\
& =2 P E \quad\left(\because \theta_f=180^{\circ} \text { and } \theta_i=0^{\circ}\right) \\
& =\left(2 \times 6 \times 10^{-6} \times 10^6\right) \mathrm{J}=12 \mathrm{~J}
\end{aligned}\)
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