JEE Mains · Physics · STD 12 - 3. current electricity
For the given circuit, in the steady state, \(\left| V _{ B }- V _{ D }\right|=.......V.\)
- A \(2\)
- B \(3\)
- C \(1\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
In steady state, capacitor behaves as an open circuit. Circuit is \(i_{A B}=\frac{6}{3}=2 A\) \(i_{A D}=\frac{6}{12}=0.5 A\) \(V_B+2 \times 2-10 \times 0.5=V_D\) \(V_B-V_D=1\;volt\)
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