JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2023
- Hard
- Numerical
For the given circuit, in the steady state, \(\left| V _{ B }- V _{ D }\right|=.......V.\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
In steady state, capacitor behaves as an open circuit. Circuit is
\(i_{A B}=\frac{6}{3}=2 A\)
\(i_{A D}=\frac{6}{12}=0.5 A\)
\(V_B+2 \times 2-10 \times 0.5=V_D\)
\(V_B-V_D=1\;volt\)
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