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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Hard
  • Numerical

For the given circuit, in the steady state, \(\left| V _{ B }- V _{ D }\right|=.......V.\)

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Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

In steady state, capacitor behaves as an open circuit. Circuit is

\(i_{A B}=\frac{6}{3}=2 A\)

\(i_{A D}=\frac{6}{12}=0.5 A\)

\(V_B+2 \times 2-10 \times 0.5=V_D\)

\(V_B-V_D=1\;volt\)

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