JEE Mains · Physics · STD 11 - 11. thermodynamics
A sample of an ideal gas is taken through the cyclic process \(abca\) as shown in the figure. The change in the internal energy of the gas along the path \(ca\) is \(-180\, J\). The gas absorbs \(250\, J\) of heat along the path \(ab\) and \(60\, J\) along the path \(bc\). The work done by the gas along the path \(abc\) is ..... \(J\)
- A \(120\)
- B \(100\)
- C \(140\)
- D \(130\)
Answer & Solution
Correct Answer
(D) \(130\)
Step-by-step Solution
Detailed explanation
\(\Delta\,E\) \(\Delta\,W\) \(\Delta\,Q\) \(ab\) \(250\) \(bc\) \(0\) \(60\) \(ca\) \(-180\) \(\Delta\,E\) \(\Delta\,W\) \(\Delta\,Q\) \(ab\) \(120\) \(130\) \(250\) \(bc\) \(60\) \(0\) \(60\) \(ca\) \(-180\)
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