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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2025
  • Medium
  • MCQ

An electric dipole is placed at a distance of 2 cm from an infinite plane sheet having positive charge density \(\sigma_{\mathrm{o}}\). Choose the correct option from the following.

Pick an option to check your answer.
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Answer & Solution

Correct Answer

(D) Potential energy of dipole is minimum and torque is zero.

Step-by-step Solution

Detailed explanation

Electric field due to sheet \(E=\frac{\sigma}{2 \varepsilon_0}\)
and torque on dipole \(\vec{\tau}=\vec{P} \times \vec{E}\)
here \(\vec{\tau}=0\)
and \(U=-\vec{P} \cdot \vec{E} \rightarrow\) should be minimum
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