JEE Mains · Physics · STD 12 - Atoms
- JEE Mains 2024
- Hard
- Numerical
A particular hydrogen - like ion emits the radiation of frequency \(3 \times 10^{15} \mathrm{~Hz}\) when it makes transition from \(n=2\) to \(n=1\). The frequency of radiation emitted in transition from \(n=3\) to \(n=1\) is \(\frac{x}{9} \times 10^{15} \mathrm{~Hz}\), when \(x=\) = _____.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(32\)
Step-by-step Solution
Detailed explanation
\(E=-13.6 z^2\left(\frac{1}{n_i^2}-\frac{1}{n_f^2}\right)\)
\(\mathrm{E}=\mathrm{C}\left(\frac{1}{\mathrm{n}_{\mathrm{f}}^2}-\frac{1}{\mathrm{n}_{\mathrm{i}}^2}\right)\)
\(\mathrm{h} \nu=\mathrm{C}\left[\frac{1}{\mathrm{n}_{\mathrm{f}}^2}-\frac{1}{\mathrm{n}_{\mathrm{i}}^2}\right]\)
\(\frac{v_1}{v_2}=\frac{\left[\frac{1}{n_f^2}-\frac{1}{n_i^2}\right]_{2-1}}{\left[\frac{1}{n_f^2}-\frac{1}{n_i^2}\right]_{3-1}}\)
\(=\frac{\left[\frac{1}{1}-\frac{1}{4}\right]}{\left[\frac{1}{1}-\frac{1}{9}\right]}=\frac{3 / 4}{8 / 9}\)
\(=\frac{3}{4} \times \frac{9}{8}\)
\(\frac{v_1}{v_2}=\frac{27}{32}\)
\(v_2=\frac{32}{27} v_1=\frac{32}{27} \times 3 \times 10^{15} \mathrm{~Hz}=\frac{32}{9} \times 10^{15} \mathrm{~Hz}\)
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