JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
A cylindrical container of volume \(4.0 \times 10^{-3} \,{m}^{3}\) contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is \(400 \,{K}\) The pressure of the mixture of gases is: [Take gas constant as \(8.3\, {J} {mol}^{-1} {K}^{-1}\)]
- A \(249 \, \times 10^{1} {Pa}\)
- B \(24.9 \, \times 10^{3} {Pa}\)
- C \(24.9 \, \times 10^{5} {Pa}\)
- D \(24.9 \,{Pa}\)
Answer & Solution
Correct Answer
(C) \(24.9 \, \times 10^{5} {Pa}\)
Step-by-step Solution
Detailed explanation
\({V}=4 \times 10^{-3} \,{m}^{3}\) \({n}=3\) \(moles\) \({T}=400\, {K}\) \({PV}={nRT} \Rightarrow {P}=\frac{{nRT}}{{V}}\) \({P}=\frac{3 \times 8.3 \times 400}{4 \times 10^{-3}}\) \(=24.9 \times 10^{5} \,{Pa}\)
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