A cylindrical container of volume \(4.0 \times 10^{-3} \,{m}^{3}\) contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is \(400 \,{K}\) The pressure of the mixture of gases is: [Take gas constant as \(8.3\, {J} {mol}^{-1} {K}^{-1}\)]

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Answer & Solution

Correct Answer

(C) \(24.9 \, \times 10^{5} {Pa}\)

Step-by-step Solution

Detailed explanation

\({V}=4 \times 10^{-3} \,{m}^{3}\)

\({n}=3\) \(moles\)

\({T}=400\, {K}\)

\({PV}={nRT} \Rightarrow {P}=\frac{{nRT}}{{V}}\)

\({P}=\frac{3 \times 8.3 \times 400}{4 \times 10^{-3}}\)

\(=24.9 \times 10^{5} \,{Pa}\)

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