JEE Mains · Physics · STD 12 -7. Alternating current
An ac circuit has an inductor and a resistor of resistance \({R}\) in series, such that \({X}_{{L}}=3 {R}\). Now, a capacitor is added in series such that \({X}_{{C}}=2 {R}\). The ratio of new power factor with the old power factor of the circuit is \(\sqrt{5}: {x}\). The value of \({x}\) is ...... .
- A \(2\)
- B \(1\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\(\cos \phi=\frac{{R}}{\sqrt{{R}^{2}+3 {R}^{2}}}\) \(=\frac{1}{\sqrt{10}}\) \(\cos \phi^{\prime}=\frac{{R}}{\sqrt{{R}^{2}+{R}^{2}}}\) \(=\frac{1}{\sqrt{2}}\) \(\frac{\cos \phi^{\prime}}{\cos \phi}=\frac{\sqrt{10}}{\sqrt{2}}=\frac{\sqrt{5}}{1}\) \(\therefore {x}=1\)
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