JEE Mains · Physics · STD 12 - 10. Wave optics
A beam of light consisting of two wavelengths \(7000\; \mathring A\) and \(5500 \;\mathring A\) is used to obtain interference pattern in Young's double slit experiment. The distance between the slits is \(2.5\,mm\) and the distance between the plane of slits and the screen is \(150\,cm\). The least distance from the central fringe, where the bright fringes due to both the wavelengths coincide, is \(n \times 10^{-5}\,m\). The value of \(n\) is .............
- A \(461\)
- B \(460\)
- C \(462\)
- D \(469\)
Answer & Solution
Correct Answer
(C) \(462\)
Step-by-step Solution
Detailed explanation
\(d =2.5\,mm , D =150\,cm\) Fringe width \(\beta=\frac{\lambda D}{d}\) Let \(n^{\text {th }}\) bright tringle of \(\lambda_1\) match with \(m ^{\text {th }}\) bright triangle of \(\lambda_2\) \(\Rightarrow n \beta_1=m \beta_2\)…
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