JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
An object is located in a fixed position in front of a screen. Sharp image is obtained on the screen for two positions of a thin lens separated by \(10\, cm\). The size of the images in two situations are in the ratio \(3 : 2\). What is the distance between the screen and the object?......\(cm\)
- A \(124.5\)
- B \(144.5\)
- C \(65\)
- D \(99\)
Answer & Solution
Correct Answer
(D) \(99\)
Step-by-step Solution
Detailed explanation
Given: Separation of lens for two of its position, \(d=10 \mathrm{cm}\) Ratio of size of the images in two positions \(\frac{I_{1}}{I_{2}}=\frac{3}{2}\) Distance of object from the screen, \(D=?\) Applying formula,…
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