JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2021
- Medium
- Numerical
A system consists of two types of gas molecules \(A\) and \(B\) having same number density \(2 \times\) \(10^{25}\, / {m}^{3}\). The diameter of \({A}\) and \({B}\) are \(10\, \stackrel{\circ}{{A}}\) and \(5\, \stackrel{\circ}{{A}}\) respectively. They suffer collision at room temperature. The ratio of average distance covererd by the molecule \(A\) to that of \(B\) between two successive collision is \(.....\,\times 10^{-2}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(25\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{1}{\sqrt{2} \pi d ^{2} n }\)
\(\frac{\lambda_{1}}{\lambda_{2}}=\frac{ d _{2}^{2} n _{2}}{ d _{1}^{2} n _{1}}\)
\(=\left(\frac{5}{10}\right)^{2}=0.25=25 \times 10^{-2}\)
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