ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion

A hollow spherical ball of uniform density rolls up a curved surface with an initial velocity \(3\, m / s\) (as shown in figure). Maximum height with respect to the initial position covered by it will be \(...........cm\).

  1. A \(75\)
  2. B \(74\)
  3. C \(73\)
  4. D \(72\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(75\)

Step-by-step Solution

Detailed explanation

At highest point \(KE _{ f }=0\) Initial \(KE =\) Translational \(KE +\) Rotational \(KE\) \(=\frac{1}{2} mv ^2+\frac{1}{2} I \omega^2\) In case of rolling \(v = R \omega\) \(=\frac{1}{2} m v^2+\frac{1}{2} \times \frac{2}{3} m R^2 \times \frac{v^2}{R^2}\) \(=\frac{5}{6} m v^2\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app