JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A hollow spherical ball of uniform density rolls up a curved surface with an initial velocity \(3\, m / s\) (as shown in figure). Maximum height with respect to the initial position covered by it will be \(...........cm\).

- A \(75\)
- B \(74\)
- C \(73\)
- D \(72\)
Answer & Solution
Correct Answer
(A) \(75\)
Step-by-step Solution
Detailed explanation
At highest point \(KE _{ f }=0\) Initial \(KE =\) Translational \(KE +\) Rotational \(KE\) \(=\frac{1}{2} mv ^2+\frac{1}{2} I \omega^2\) In case of rolling \(v = R \omega\) \(=\frac{1}{2} m v^2+\frac{1}{2} \times \frac{2}{3} m R^2 \times \frac{v^2}{R^2}\) \(=\frac{5}{6} m v^2\)…
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