JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2021
- Hard
- Numerical
Calculate the value of mean free path \((\lambda)\) for oxygen molecules at temperature \(27^{\circ}\, C\) and pressure \(1.01 \times 10^{5} \,Pa\). Assume the molecular diameter \(0.3 \,nm\) and the gas is ideal. \(\left( k =1.38 \times 10^{-23}\, J\,K ^{-1}\right)\) (in \(nm\))
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(102\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{ RT }{\sqrt{2} \pi d ^{2} N _{ A } P }\)
\(\lambda=102\, nm\)
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