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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Medium
  • Numerical

In a meter bridge experiment the balance point in obtained if the gaps are closed by \(2\,\Omega\) and \(3\,\Omega\). A shunt of \(x\,\Omega\) is added to \(3\,\Omega\) resistor to shift the balancing point by \(22.5\,cm\). The value of \(X\) is \(................\)

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Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

\(\frac{2}{\left(\frac{3 x}{3+x}\right)}=\frac{40+22.5}{60-22.5}=\frac{62.5}{37.5}=\frac{5}{3}\)

\(\frac{6}{5}=\frac{3 x}{3+x}\)

\(6+2 x=5 x \Rightarrow x=2\)

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