JEE Mains · Physics · STD 11 - 13. oscillations
A spring of force constant \(15 N / m\) is cut into two pieces. If the ratio of their length is \(1: 3\), then the force constant of smaller piece is _________ N/m
- A 15
- B 20
- C 60
- D 45
Answer & Solution
Correct Answer
(C) 60
Step-by-step Solution
Detailed explanation
\(K \ell=\) constant \(K \ell= K ^{\prime}\left(\frac{\ell}{4}\right)\) \(K ^{\prime}=4 K\) \(K ^{\prime}=60 N / m\)
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