JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2026
- Easy
- MCQ
A spring of force constant \(15 N / m\) is cut into two pieces. If the ratio of their length is \(1: 3\), then the force constant of smaller piece is _________ N/m
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) 60
Step-by-step Solution
Detailed explanation

\(K \ell=\) constant
\(K \ell= K ^{\prime}\left(\frac{\ell}{4}\right)\)
\(K ^{\prime}=4 K\)
\(K ^{\prime}=60 N / m\)
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