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JEE Mains · Physics · STD 11 - 3.2 motion in plane

Two objects are projected with same velocity ' \(u\) ' however at different angles \(\alpha\) and \(\beta\) with the horizontal. If \(\alpha+\beta=90^{\circ}\), the ratio of horizontal range of the first object to the \(2^{\text {nd }}\) object will be :

  1. A \(4: 1\)
  2. B \(2: 1\)
  3. C \(1: 2\)
  4. D \(1: 1\)
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Answer & Solution

Correct Answer

(D) \(1: 1\)

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Detailed explanation

\(\text { Range }=\frac{ u ^2 \sin 2 \theta}{ g }\) Range for projection angle " \(\alpha\) " \(R _1=\frac{ u ^2 \sin 2 \alpha}{ g }\) Range for projection angle " \(\beta\) " \(R _2=\frac{ u ^2 \sin 2 \beta}{ g }\) \(\alpha+\beta=90^{\circ}(\text { Given })\)…
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