JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2023
- Medium
- MCQ
Two objects are projected with same velocity ' \(u\) ' however at different angles \(\alpha\) and \(\beta\) with the horizontal. If \(\alpha+\beta=90^{\circ}\), the ratio of horizontal range of the first object to the \(2^{\text {nd }}\) object will be :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(1: 1\)
Step-by-step Solution
Detailed explanation
\(\text { Range }=\frac{ u ^2 \sin 2 \theta}{ g }\)
Range for projection angle " \(\alpha\) "
\(R _1=\frac{ u ^2 \sin 2 \alpha}{ g }\)
Range for projection angle " \(\beta\) "
\(R _2=\frac{ u ^2 \sin 2 \beta}{ g }\)
\(\alpha+\beta=90^{\circ}(\text { Given })\)
\(\Rightarrow \beta=90^{\circ}-\alpha\)
\(R _2=\frac{ u ^2 \sin 2\left(90^{\circ}-\alpha\right)}{ g }\)
\(R _2=\frac{ u ^2 \sin \left(180^{\circ}-2 \alpha\right)}{ g }\)
\(R _2=\frac{ u ^2 \sin 2 \alpha}{ g }\)
\(\Rightarrow \frac{ R _1}{ R _2}=\frac{\left(\frac{ u ^2 \sin 2 \alpha}{ g }\right)}{\left(\frac{ u ^2 \sin 2 \alpha}{ g }\right)}=\frac{1}{1}\)
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