JEE Mains · Physics · STD 12 - 12. atoms
An electron rotates in a circle around a nucleus having positive charge \(\mathrm{Ze}\). Correct relation between total energy ( \(E\) ) of electron to its potential energy \((U)\) is _______.
- A \(\mathrm{E}=2 \mathrm{U}\)
- B \(2 \mathrm{E}=3 \mathrm{U}\)
- C \(E=U\)
- D \(2 E=U\)
Answer & Solution
Correct Answer
(D) \(2 E=U\)
Step-by-step Solution
Detailed explanation
\(\mathrm{F}=\frac{\mathrm{k}(\mathrm{Ze})(\mathrm{e})}{\mathrm{r}^2}=\frac{\mathrm{mv}^2}{\mathrm{r}}\) \(\mathrm{KE}=\frac{1}{2} \mathrm{mv}^2=\frac{1}{2} \frac{\mathrm{K}(\mathrm{Ze})(\mathrm{e})}{\mathrm{r}}\)…
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