JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A small square loop of wire of side \(\ell\) is placed inside a large square loop of wire of side \(L\) \(\left(\mathrm{L}=\ell^2\right)\). The loops are coplanar and therr centers coinside. The value of the mutual inductance of the system is \(\sqrt{\mathrm{x}} \times 10^{-7} \mathrm{H}\), where X = _______.
- A \(120\)
- B \(125\)
- C \(128\)
- D \(130\)
Answer & Solution
Correct Answer
(C) \(128\)
Step-by-step Solution
Detailed explanation
Flux linkage for inner loop. \(\phi=\mathrm{B}_{\text {crater }} \ell^2\) \(=4 \times \frac{\mu_0 \mathrm{i}}{4 \pi \frac{\mathrm{L}}{2}}(\sin 45+\sin 45) \ell^2\) \(\phi=2 \sqrt{2} \frac{\mu_0 \mathrm{i}}{\pi \mathrm{L}} \ell^2\)…
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