JEE Mains · Physics · STD 11 - 7. gravitation
The time period of a satellite in a circular orbit of radius \(R\) is \(T\). The period of another satellite in a circular orbit of radius \(9 R\) is............ \(T\)
- A \(9\)
- B \(27\)
- C \(12\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(27\)
Step-by-step Solution
Detailed explanation
\(T ^{2} \propto R ^{3}\) \(\left(\frac{ T ^{\prime}}{ T }\right)^{2}=\left(\frac{9 R }{ R }\right)^{3}\) \(T ^{2}= T ^{2} \times 9^{3}\) \(T ^{\prime}= T \times 3^{3}\) \(T ^{\prime}=27 T\)
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