JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A singly ionized magnesium atom \((A=24)\) ion is accelerated to kinetic energy \(5\,keV\) and is projected perpendicularly into a magnetic field \(B\) of the magnitude \(0.5\,T\). The radius of path formed will be___________ \(cm\)
- A \(9\)
- B \(3\)
- C \(7\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
\(R =\frac{ mv }{ qB }=\frac{\sqrt{2 mK }}{ qB }\)
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