JEE Mains · Physics · STD 11 - Fluid mechanics
- JEE Mains 2022
- Medium
- MCQ
The bulk modulus of a liquid is \(3 \times 10^{10}\, Nm ^{-2}\). The pressure required to reduce the volume of liquid by \(2 \%\) is ........ \(\times 10^{8}\; Nm ^{-2}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
\(B =3 \times 10^{10}\)
\(-\frac{\Delta V }{ V }=0.02\)
\(B =\frac{\Delta P }{-\frac{\Delta V }{ V }} \Rightarrow \Delta P =- B \left(\frac{\Delta V }{ V }\right)\)
\(=\left(3 \times 10^{10}\right)(0.02)\)
\(=6 \times 10^{8} N / m ^{2}\)
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