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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2022
  • Medium
  • MCQ

The bulk modulus of a liquid is \(3 \times 10^{10}\, Nm ^{-2}\). The pressure required to reduce the volume of liquid by \(2 \%\) is  ........ \(\times 10^{8}\; Nm ^{-2}\)

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Answer & Solution

Correct Answer

(C) \(6\)

Step-by-step Solution

Detailed explanation

\(B =3 \times 10^{10}\)

\(-\frac{\Delta V }{ V }=0.02\)

\(B =\frac{\Delta P }{-\frac{\Delta V }{ V }} \Rightarrow \Delta P =- B \left(\frac{\Delta V }{ V }\right)\)

\(=\left(3 \times 10^{10}\right)(0.02)\)

\(=6 \times 10^{8} N / m ^{2}\)

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