JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
The bulk modulus of a liquid is \(3 \times 10^{10}\, Nm ^{-2}\). The pressure required to reduce the volume of liquid by \(2 \%\) is ........ \(\times 10^{8}\; Nm ^{-2}\)
- A \(3\)
- B \(9\)
- C \(6\)
- D \(12\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
\(B =3 \times 10^{10}\) \(-\frac{\Delta V }{ V }=0.02\) \(B =\frac{\Delta P }{-\frac{\Delta V }{ V }} \Rightarrow \Delta P =- B \left(\frac{\Delta V }{ V }\right)\) \(=\left(3 \times 10^{10}\right)(0.02)\) \(=6 \times 10^{8} N / m ^{2}\)
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