JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2022
- Easy
- Numerical
In the wave equation \(y =0.5 \sin \frac{2 \pi}{\lambda}(400 t - x )\,m\) the velocity of the wave will be ......... \(m / s\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(400\)
Step-by-step Solution
Detailed explanation
\(y =0.5 \sin \left(\frac{2 \pi}{\lambda} 400 t -\frac{2 \pi}{\lambda} x \right)\)
\(\omega=\frac{2 \pi}{\lambda} 400\)
\(K =\frac{2 \pi}{\lambda}\)
\(v =\frac{\omega}{ k } \quad[ v =400\,m / s ]\)
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