JEE Mains · Physics · STD 11 - 14. waves and sound
In the wave equation \(y =0.5 \sin \frac{2 \pi}{\lambda}(400 t - x )\,m\) the velocity of the wave will be ......... \(m / s\)
- A \(200\)
- B \(200 \sqrt{2}\)
- C \(400\)
- D \(400 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(400\)
Step-by-step Solution
Detailed explanation
\(y =0.5 \sin \left(\frac{2 \pi}{\lambda} 400 t -\frac{2 \pi}{\lambda} x \right)\) \(\omega=\frac{2 \pi}{\lambda} 400\) \(K =\frac{2 \pi}{\lambda}\) \(v =\frac{\omega}{ k } \quad[ v =400\,m / s ]\)
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