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JEE Mains · Physics · STD 12 - 13. Nuclei

A sample of radioactive material \(A\), that has an activity of \(10\, mCi\, (1\, Ci = 3.7 \times 10^{10}\, decays/s)\), has twice the number of nuclei as another sample of different radioactive material \(B\) which has an activity of \(20\, mCi\). The correct choices for half-lives of \(A\) and \(B\) would then be respectively

  1. A \(5\) days and \(10\) days
  2. B \(10\) days and \(40\) days
  3. C \(20\) days and \(5\) days
  4. D \(20\) days and \(10\) days
Verified Solution

Answer & Solution

Correct Answer

(B) \(10\) days and \(40\) days

Step-by-step Solution

Detailed explanation

Activity \(=\lambda\) (number of atoms) \(10=\lambda_{A} N_{A}\) ..... \((1)\) \(20=\lambda_{B} N_{B}\) ..... \((2)\) \(N_{A}=2 N_{B}\) ..... \((3)\) Solving we get, \(\frac{\lambda_{A}}{\lambda_{B}}=\frac{1}{4}\)
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