JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A proton, a deuteron and an \(\alpha-\)particle with same kinetic energy enter into a uniform magnetic field at right angle to magnetic field. The ratio of the radii of their respective circular paths is
- A \(1: \sqrt{2}: \sqrt{2}\)
- B \(1: 1: \sqrt{2}\)
- C \(\sqrt{2}: 1: 1\)
- D \(1: \sqrt{2}: 1\)
Answer & Solution
Correct Answer
(D) \(1: \sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
\(R =\frac{\sqrt{2 \,km }}{ qB } \propto \frac{\sqrt{ m }}{ q }\) \(\frac{\sqrt{ m }}{ e }: \frac{\sqrt{2 \,m }}{ e }: \frac{\sqrt{4\, m }}{2 e }\) \(1: \sqrt{2}: 1\)
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