JEE Mains · Physics · STD 11 - 7. gravitation
A satellite is launched into a circular orbit of radius ' R ' around the earth. A second satellite is launched into an orbit of radius 1.03 R . The time period of revolution of the second satellite is larger than the first one approximately by
- A \(9 \%\)
- B \(3 \%\)
- C \(4.5 \%\)
- D \(2.5 \%\)
Answer & Solution
Correct Answer
(C) \(4.5 \%\)
Step-by-step Solution
Detailed explanation
\(T_1 \propto(R)^{3 / 2}\) and \(T_2 \propto(1.03 R)^{3 / 2}\) \(\Rightarrow \quad T_2=(1.03 R)^{3 / 2} \cdot T_1 \approx 1.045 T_1\) So \(T_2\) will larger by \(4.5 \%\) w.r.t. \(T_1\).
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