JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2019
- Medium
- MCQ
Young’s moduli of two wires \(A\) and \(B\) are in the ratio \(7 : 4\). Wire \(A\) is \(2\, m\) long and has radius \(R\). Wire \(A\) is \(2\, m\) long and has radius \(R\). Wire \(B\) is \(1.5\, m\) long and has radius \(2\, mm\). If the two wires stretch by the same length for a given load, then the value of \(R\) is close to ......... \(mm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(1.7\)
Step-by-step Solution
Detailed explanation
Given:
\(\frac{{{Y_A}}}{{{Y_B}}} = \frac{7}{4}\,\,\,{L_A} = 2m\,\,\,{A_A} = \pi {R^2}\)
\({L_B} = 1.5\,m\,\,\,\,\,\,\,\,{A_B} = \pi {\left( {2mm} \right)^2}\)
\(\frac{F}{A} = Y\left( {\frac{\ell }{L}} \right)\)
\(given\,F\,and\,\ell \,are\,same \Rightarrow \frac{{AY}}{L}\,is\,same\)
\(\frac{{{A_A}{Y_A}}}{{{L_A}}} = \frac{{{A_B}{Y_B}}}{{{L_B}}}\)
\( \Rightarrow \frac{{\left( {\pi {R^2}} \right)\left( {\frac{7}{4}{Y_B}} \right)}}{2} = \frac{{\pi {{\left( {2\,mm} \right)}^2}.{Y_B}}}{{1.5}}\)
\(R = 1.74\,mm\)
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