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JEE Mains · Physics · STD 11- Mechanical properties of solids
  • JEE Mains 2019
  • Medium
  • MCQ

Young’s moduli of two wires \(A\) and \(B\) are in the ratio \(7 : 4\). Wire \(A\) is \(2\, m\) long and has radius \(R\). Wire \(A\) is \(2\, m\) long and has radius \(R\). Wire \(B\) is \(1.5\, m\) long and has radius \(2\, mm\). If the two wires stretch by the same length for a given load, then the value of \(R\) is close to ......... \(mm\)

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Answer & Solution

Correct Answer

(C) \(1.7\)

Step-by-step Solution

Detailed explanation

Given:

\(\frac{{{Y_A}}}{{{Y_B}}} = \frac{7}{4}\,\,\,{L_A} = 2m\,\,\,{A_A} = \pi {R^2}\)

                     \({L_B} = 1.5\,m\,\,\,\,\,\,\,\,{A_B} = \pi {\left( {2mm} \right)^2}\)

\(\frac{F}{A} = Y\left( {\frac{\ell }{L}} \right)\)

\(given\,F\,and\,\ell \,are\,same \Rightarrow \frac{{AY}}{L}\,is\,same\)

\(\frac{{{A_A}{Y_A}}}{{{L_A}}} = \frac{{{A_B}{Y_B}}}{{{L_B}}}\)

\( \Rightarrow \frac{{\left( {\pi {R^2}} \right)\left( {\frac{7}{4}{Y_B}} \right)}}{2} = \frac{{\pi {{\left( {2\,mm} \right)}^2}.{Y_B}}}{{1.5}}\)

\(R = 1.74\,mm\)

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