JEE Mains · Physics · STD 11 - 7. gravitation
When one moves from a point \(16\) km below the earth's surface to a point \(16\) km above the earth's surface. The change in \(g\) is approximately \(\alpha\) %. The value of \(\alpha\) is _____.
(Take radius of the earth \(= 6400\) km.)
- A \(0.12\)
- B \(0.25\)
- C \(0.50\)
- D \(0.75\)
Answer & Solution
Correct Answer
(B) \(0.25\)
Step-by-step Solution
Detailed explanation
The acceleration due to gravity at a depth \(d\) below the earth's surface is given by: \(g_d = g\left(1 - \dfrac{d}{R}\right)\) The acceleration due to gravity at a height \(h\) above the earth's surface (for \(h \ll R\)) is given by: \(g_h = g\left(1 - \dfrac{2h}{R}\right)\)…
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