JEE Mains · Physics · STD 11 - 11. thermodynamics
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The rational between temperature and volume for the process is \(TV^x =\) constant, then \(x\) is
- A \(3/5\)
- B \(2/5\)
- C \(2/3\)
- D \(5/3\)
Answer & Solution
Correct Answer
(B) \(2/5\)
Step-by-step Solution
Detailed explanation
Equation of adiabatic process \(TV^{2/f} =\) constant \(\therefore \,\,\frac {2}{f}=\frac {2}{5}=x\)
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