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JEE Mains · Physics · STD 11 - 11. thermodynamics

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The rational between temperature and volume for the process is \(TV^x =\) constant, then \(x\) is

  1. A \(3/5\)
  2. B \(2/5\)
  3. C \(2/3\)
  4. D \(5/3\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2/5\)

Step-by-step Solution

Detailed explanation

Equation of adiabatic process \(TV^{2/f} =\) constant \(\therefore \,\,\frac {2}{f}=\frac {2}{5}=x\)
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