ExamBro
ExamBro
JEE Mains · Physics · STD 12 -7. Alternating current

Using a variable-frequency a.c. voltage source, the maximum current measured in the given LCR circuit is 50 mA for \(V =5 \sin (100 t )\). The values of L and \(R\) are shown in the figure. The capacitance of the capacitor \(( C )\) used is ___________ \(\mu F\).
image

  1. A 25
  2. B 50
  3. C 75
  4. D 100
Verified Solution

Answer & Solution

Correct Answer

(B) 50

Step-by-step Solution

Detailed explanation

Current is maximum, so resonance and \(\omega=\frac{1}{\sqrt{ LC }}\) \(C=\frac{1}{\omega^2 L}=\frac{1}{2 \times 10^4}\) \(=50 \times 10^{-6}=50 \mu F\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app