JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2026
- Hard
- Numerical
Using a variable-frequency a.c. voltage source, the maximum current measured in the given LCR circuit is 50 mA for \(V =5 \sin (100 t )\). The values of L and \(R\) are shown in the figure. The capacitance of the capacitor \(( C )\) used is ___________ \(\mu F\).

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) 50
Step-by-step Solution
Detailed explanation
Current is maximum, so resonance
and \(\omega=\frac{1}{\sqrt{ LC }}\)
\(C=\frac{1}{\omega^2 L}=\frac{1}{2 \times 10^4}\)
\(=50 \times 10^{-6}=50 \mu F\)
and \(\omega=\frac{1}{\sqrt{ LC }}\)
\(C=\frac{1}{\omega^2 L}=\frac{1}{2 \times 10^4}\)
\(=50 \times 10^{-6}=50 \mu F\)
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