JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2021
- Hard
- Numerical
A reversible engine has an efficiency of \(\frac{1}{4}\). If the temperature of the sink is reduced by \(58^{\circ} {C}\), its efficiency becomes double. Calculate the temperature of the sink. (In \(^{\circ} {C}\))
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(174\)
Step-by-step Solution
Detailed explanation
\({T}_{2}=\) sink temperature
\(\eta=1-\frac{{T}_{2}}{{T}_{1}}\)
\(\frac{1}{4}=1-\frac{{T}_{2}}{{T}_{1}}\)
\(\frac{{T}_{2}}{{T}_{1}}=\frac{3}{4} \ldots\) \((i)\)
\(\frac{1}{2}=1-\frac{{T}_{2}-58}{{T}_{1}}\)
\(\frac{{T}_{2}}{{T}_{1}}-\frac{58}{{T}_{1}}=\frac{1}{2}\)
\(\frac{3}{4}=\frac{58}{{T}_{1}}+\frac{1}{2}\)
\(\frac{1}{4}=\frac{58}{{T}_{1}} \Rightarrow {T}_{1}=232\)
\({T}_{2}=\frac{3}{4} \times 232\)
\({T}_{2}=174\, {K}\)
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