ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2024
  • Hard
  • MCQ

A simple pendulum doing small oscillations at a place \(\mathrm{R}\) height above earth surface has time period of \(T_1=4 \mathrm{~s}\). \(T_2\) would be it's time period if it is brought to a point which is at a height \(2 R\) from earth surface. Choose the correct relation. \([R=\) radius of Earth]:

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(C) \(3 \mathrm{~T}_1=2 \mathrm{~T}_2\)

Step-by-step Solution

Detailed explanation

\(\mathrm{T}_1=2 \pi \sqrt{\frac{\ell}{\mathrm{GM}}(2 \mathrm{R})^2}\)

\(\mathrm{~T}_2=2 \pi \sqrt{\frac{\ell}{\mathrm{GM}}(3 \mathrm{R})^2}\)

\(\therefore \frac{\mathrm{T}_1}{\mathrm{~T}_2}=\frac{2}{3}\)

Same subject
Explore more questions on app