JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A particle is moving in a circular path of radius \(a,\) with a constant velocity \(v\) as shown in the figure.The centre of circle is marked by \('C'\). The angular momentum from the origin \(O\) can be written as
- A \(va\,\, ( 1 + cos\,2\theta )\)
- B \(va\,\, ( 1 + cos\,\theta )\)
- C \(va\,\,cos\,2\theta \)
- D \(va\)
Answer & Solution
Correct Answer
(A) \(va\,\, ( 1 + cos\,2\theta )\)
Step-by-step Solution
Detailed explanation
\((v \cos \theta) \times 2\) turns \(2 \cos v a-1=\cos 2 w\) \(2 \mathrm{rv} \cos ^{2} \mathrm{v}\) va \((1+\cos 2 \theta)\)
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