JEE Mains · Physics · STD 11 - 11. thermodynamics
A refrigerator consumes an average \(35\, {W}\) power to operate between temperature \(-10^{\circ} {C}\) to \(25^{\circ} {C}\). If there is no loss of energy then how much average heat per second does it transfer? (in \({J} / {s}\))
- A \(263\)
- B \(298\)
- C \(350\)
- D \(35\)
Answer & Solution
Correct Answer
(A) \(263\)
Step-by-step Solution
Detailed explanation
\(\frac{{T}_{{L}}}{{T}_{{H}}-{T}_{{L}}}={C} . {O} \cdot {P} .=\frac{\frac{{dH}}{{dt}}}{\frac{{dW}}{{dt}}}\) \(\frac{263}{35} \times 35=\frac{{dH}}{{dt}}\) \(\frac{{dH}}{{dt}}=263\) \(watts\)
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